#include<iostream>
using namespace std;
int main()
{
int n,nr,p=0,sum=0,i,max;
cout<<"n=";cin>>n;
cout<<"Nr=";cin>>nr;
max=nr;
if(nr%2==0)p++;
if(nr>0)sum=sum+nr;
for(i=1;i<n;i++){cout<<"Nr=";cin>>nr;if(nr%2==0)p++;if(nr>0)sum=sum+nr;if(nr>max)max=nr;}
cout<<"Nr pare:"<<p<<endl;
cout<<"Suma elementelor pozitive:"<<sum<<endl;
cout<<"Nr max:"<<max;
}
Acest blog a fost facut pentru a ajuta oamenii ce nu stiu informatica dar ar vrea sa invete.
miercuri, 5 martie 2014
Sa se afiseze media aritmetica a trei numere si sa afiseze un mesaj corespunzator daca formeaza triplet pitagoric.
#include<iostream>
using namespace std;
int main()
{
int m,n,p,s;
cout<<"m=";cin>>m;
cout<<"n=";cin>>n;
cout<<"p=";cin>>p;
s=m+n+p;
cout<<"Media aritmetica="<<s/3<<endl;
if(m*m+n*n==p*p || m*m+p*p==n*n || p*p+n*n==m*m)cout<<"formeaza triplet pitagoric";
}
using namespace std;
int main()
{
int m,n,p,s;
cout<<"m=";cin>>m;
cout<<"n=";cin>>n;
cout<<"p=";cin>>p;
s=m+n+p;
cout<<"Media aritmetica="<<s/3<<endl;
if(m*m+n*n==p*p || m*m+p*p==n*n || p*p+n*n==m*m)cout<<"formeaza triplet pitagoric";
}
De la tastatura se citesc tri numere reale a,b si c.Daca cele trei numere pot forma laturile unui triunghi,sa se afiseze pe ecran un mesaj corespunzator.
#include<iostream>
using namespace std;
int main()
{
int a,b,c;
cout<<"a=";cin>>a;
cout<<"b=";cin>>b;
cout<<"c=";cin>>c;
if((a<b+c)&&(b<a+c)&&(c<b+a)){cout<<"Formeaza triunghi";
if((a==b)&&(b==c))cout<<":echilateral";
else if(a==b || a==c || b==c)cout<<":isoscel";
if(a*a+b*b==c*c || b*b+c*c==a*a || a*a+c*c==b*b)cout<<":dreptunghic";}
else cout<<"Nu formeaza triunghi";
}
using namespace std;
int main()
{
int a,b,c;
cout<<"a=";cin>>a;
cout<<"b=";cin>>b;
cout<<"c=";cin>>c;
if((a<b+c)&&(b<a+c)&&(c<b+a)){cout<<"Formeaza triunghi";
if((a==b)&&(b==c))cout<<":echilateral";
else if(a==b || a==c || b==c)cout<<":isoscel";
if(a*a+b*b==c*c || b*b+c*c==a*a || a*a+c*c==b*b)cout<<":dreptunghic";}
else cout<<"Nu formeaza triunghi";
}
De la tastatura se introduce un numar n.Afisati produsul cifrelor impare.
#include<iostream>
using namespace std;
int main()
{
int n,i,x,m,p=1;
cout<<"n=";cin>>n;
m=n;
for(i=0;m!=0;i++){x=m%10;if(x%2!=0)p=p*x;m=m/10;}
cout<<p;
}
using namespace std;
int main()
{
int n,i,x,m,p=1;
cout<<"n=";cin>>n;
m=n;
for(i=0;m!=0;i++){x=m%10;if(x%2!=0)p=p*x;m=m/10;}
cout<<p;
}
marți, 4 martie 2014
Un produs are pretul unitar de x leu,la care se aplica un TVA in valoare ed t%.Sa se afisez,pe ecran,pretul de vanzare.
#include<iostream>
using namespace std;
int main()
{
float n,t;
cout<<"n=";cin>>n;
cout<<"tva=";cin>>t;
cout<<n+((n/100)*t);
}
using namespace std;
int main()
{
float n,t;
cout<<"n=";cin>>n;
cout<<"tva=";cin>>t;
cout<<n+((n/100)*t);
}
Se citeste un numar natural nenul,format exact din trei cifre.Realizati un programprin care numarul si suma cifrelor sale sa fie afisate pe linii distincte.
#include<iostream>
using namespace std;
int main()
{
int n;
cout<<"n=";cin>>n;
cout<<"Numar="<<n<<endl;
cout<<"Suma cifrelor sale="<<n/100+(n/10)%10+n%10;
}
using namespace std;
int main()
{
int n;
cout<<"n=";cin>>n;
cout<<"Numar="<<n<<endl;
cout<<"Suma cifrelor sale="<<n/100+(n/10)%10+n%10;
}
Fie s un numar natural nenul ce reprezinta un interval de timp exprimat in secunde.Sa se transforme acest interval de timp in ore,minute si secunde.
#include<iostream>
using namespace std;
int main()
{
int o,s,m,t;
cout<<"Timp in secunde:";cin>>s;
cout<<s/3600<<" ore "<<(s/60)%60<<" minute "<<s%60;
}
using namespace std;
int main()
{
int o,s,m,t;
cout<<"Timp in secunde:";cin>>s;
cout<<s/3600<<" ore "<<(s/60)%60<<" minute "<<s%60;
}
De la intrarea standard se citesc trei valori reale x,y,z.Sa se scrie un program,pentru afisarea,pe ecran.
#include<iostream>
#include<math.h>
using namespace std;
int main()
{
int x,y,z,a,b,c;
cout<<"x=";cin>>x;
cout<<"y=";cin>>y;
cout<<"z=";cin>>z;
c=(12*x+1)/(pow(y,2)+2)-sqrt(pow(z,2)+27);
b=c-3*x+5*y-45*z;
a=5*x+3*b-21*y+pow(z,4);
cout<<"a="<<a<<endl<<"b="<<b<<endl<<"c="<<c;
}
#include<math.h>
using namespace std;
int main()
{
int x,y,z,a,b,c;
cout<<"x=";cin>>x;
cout<<"y=";cin>>y;
cout<<"z=";cin>>z;
c=(12*x+1)/(pow(y,2)+2)-sqrt(pow(z,2)+27);
b=c-3*x+5*y-45*z;
a=5*x+3*b-21*y+pow(z,4);
cout<<"a="<<a<<endl<<"b="<<b<<endl<<"c="<<c;
}
Suma a 2 numere
#include<iostream>
using namespace std;
int main()
{
int a,b;
cout<<"A=";cin>>a;
cout<<"B=";cin>>b;
cout<<a+b;
}
using namespace std;
int main()
{
int a,b;
cout<<"A=";cin>>a;
cout<<"B=";cin>>b;
cout<<a+b;
}
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